document.write( "Question 1202194: The area of a rectangle is 45m^2, and the length of the rectangle is 1m more than twice the width. Find the dimensions of the rectangle.
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Algebra.Com's Answer #836845 by mananth(16946) $\"\"$ $\"About$

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The area of a rectangle is 45m^2, and the length of the rectangle is 1m more than twice the width. Find the dimensions of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "Let width be x m\r
\n" ); document.write( "\n" ); document.write( "length will be as per the info given 2x+1\r
\n" ); document.write( "\n" ); document.write( "Area of rectangle = L * width\r
\n" ); document.write( "\n" ); document.write( "x(2x+1) =45\r
\n" ); document.write( "\n" ); document.write( "2x^2 +x =45\r
\n" ); document.write( "\n" ); document.write( "2x^2+x -45=0\r
\n" ); document.write( "\n" ); document.write( "2x^2+10x-9x -45=0\r
\n" ); document.write( "\n" ); document.write( "2x(x+5)-9(x+5)=0\r
\n" ); document.write( "\n" ); document.write( "(x+5)(2x-9)=0\r
\n" ); document.write( "\n" ); document.write( "x=-5 or x= 4.5 \r
\n" ); document.write( "\n" ); document.write( "x cannot be negative
\n" ); document.write( "So x=4.5\r
\n" ); document.write( "\n" ); document.write( "Width = 4.5 m\r
\n" ); document.write( "\n" ); document.write( "Length = 2x+1 = 2(4.5)+1= 10\r
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\n" ); document.write( "\n" ); document.write( "10*4.5 =45\r
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