document.write( "Question 1202163: The incubation time for chicks is normally distributed with mean 21 days and standard deviation approximately 1 day. If 1000 eggs are being incubated, how many chicks do we expect will hatch?\r
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document.write( "a) in 19 to 23 days? \r
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document.write( "b) in 22 days or more? \r
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document.write( "c) in 21 days or fewer? \r
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document.write( "d) in 18 to 21 days? \r
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document.write( "e) in 19 days or fewer \r
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document.write( "f) in 19 to 24 days? \r
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document.write( "g) in 18 to 24 days? \r
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document.write( "h) in 18 days or more? \r
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Algebra.Com's Answer #836807 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I'll do parts (a), (b), and (c) to get you started.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "mu = 21 = population mean \n" ); document.write( "sigma = 1 = population standard deviation \n" ); document.write( "x = incubation time in days\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Find the z score when x = 19 \n" ); document.write( "z = (x - mu)/sigma \n" ); document.write( "z = (19 - 21)/1 \n" ); document.write( "z = -2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Repeat for x = 23 to get z = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The task of finding P(19 < x < 23) is the same as P(-2 < z < 2).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now use a table such as this one \n" ); document.write( "https://www.ztable.net/ \n" ); document.write( "Similar tables are found in the back of your stats textbook.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "An alternative is to use a stats calculator such as this \n" ); document.write( "https://davidmlane.com/normal.html \n" ); document.write( "However, I'll stick to using the table.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That table says: \n" ); document.write( "P(Z < -2) = 0.02275 \n" ); document.write( "and \n" ); document.write( "P(Z < 2) = 0.97725 \n" ); document.write( "Those values are approximate.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This gives \n" ); document.write( "P(a < Z < b) = P(Z < b) - P(Z < a) \n" ); document.write( "P(-2 < Z < 2) = P(Z < 2) - P(Z < -2) \n" ); document.write( "P(-2 < Z < 2) = 0.97725 - 0.02275 \n" ); document.write( "P(-2 < Z < 2) = 0.9545 \n" ); document.write( "This value is approximate.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "About 95.45% of the population is between the z scores z = -2 and z = 2. \n" ); document.write( "This translates to roughly 95.45% of the population of eggs with incubation times between x = 19 and x = 23 days.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If there are 1000 eggs being incubated, then about 0.9545*1000 = 954.5 = 955 eggs will hatch in the timeframe of 19 days to 23 days.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note that the Empirical Rule says roughly 95% of the population is within 2 standard deviations.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 955\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "======================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (b)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Find the z score when x = 22 \n" ); document.write( "z = (x - mu)/sigma \n" ); document.write( "z = (22 - 21)/1 \n" ); document.write( "z = 1 \n" ); document.write( "We are 1 standard deviation above the mean.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the z table to find that \n" ); document.write( "P(Z < 1.00) = 0.84134 \n" ); document.write( "which must mean \n" ); document.write( "P(Z > 1.00) = 1-P(Z < 1.00) \n" ); document.write( "P(Z > 1.00) = 1-0.84134 \n" ); document.write( "P(Z > 1.00) = 0.15866\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "About 15.866% of the population has an incubation time of 22 days or more.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "15.866% of 1000 = 0.15866*1000 = 158.66 = 159\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 159\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "======================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (c)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We could convert to a z score and use a table, but that might be a bit overkill here. \n" ); document.write( "50% of the population is always below the mean of a normal distribution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "50% of 1000 = 0.50*1000 = 500\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 500 \n" ); document.write( " \n" ); document.write( " |