document.write( "Question 1202166: Hi, this question is already answered on this website, but the answer is very weird and is not clear, could you explain it again?
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\n" ); document.write( "\n" ); document.write( "Sue is three times as old as Michelle. 10 years ago she was seven times as old as Michelle
\n" ); document.write( "was. How old is Sue now?
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Algebra.Com's Answer #836801 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Sue is three times as old as Michelle.

\n" ); document.write( "Starting from there...
\n" ); document.write( "let x = Michelle's age now
\n" ); document.write( "then 3x = Sue's age now (she is now three times as old as Michelle)

\n" ); document.write( "10 years ago she was seven times as old as Michelle was.

\n" ); document.write( "From our starting point above, we need expressions for their ages 10 years ago:
\n" ); document.write( "x-10 = Michelle's age 10 years ago
\n" ); document.write( "3x-10 = Sue's age 10 years ago

\n" ); document.write( "And now, using those expressions, write and solve an equation that says Sue's age 10 years ago was seven times Michelle's age 10 years ago:

\n" ); document.write( "3x-10 = 7(x-10)
\n" ); document.write( "3x-10 = 7x-70
\n" ); document.write( "60 = 4x
\n" ); document.write( "x = 15

\n" ); document.write( "How old is Sue now?:

\n" ); document.write( "ANSWER: Sue's age now is 3x = 3(15) = 45

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