document.write( "Question 1202165: Determine the appropriate base of each logarithm
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document.write( "log base b (1/15)=-1.9
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document.write( "log base b 80=3.9
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document.write( "log base b 6=0.9
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document.write( "log base b 66=3.1
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Algebra.Com's Answer #836800 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Determine the appropriate base of each logarithm \n" ); document.write( "log base b (1/15)=-1.9 \n" ); document.write( "----------- \n" ); document.write( "---> b^-1.9 = 1/15 \n" ); document.write( "Solve for b \n" ); document.write( "Using ln, natural logs, base e: \n" ); document.write( "-1.9*ln(b) = ln(1/15) \n" ); document.write( "ln(b) = ln(1/15)/(-1.9) \n" ); document.write( "ln(b) = -2.708/(-1.9) = ~1.4252 \n" ); document.write( "b = e^(1.4252) \n" ); document.write( "b =~ 4.159 \n" ); document.write( "-------------- \n" ); document.write( "=================== \n" ); document.write( "log base b 80=3.9 \n" ); document.write( "--- \n" ); document.write( "b^3.9 = 80 \n" ); document.write( "Using common logs, base 10: \n" ); document.write( "3.9*log(b) = log(80) \n" ); document.write( "log(b) = log(80)/3.9 = ~0.48797 \n" ); document.write( "b = 10^(0.48797) = ~3.0759 \n" ); document.write( "-------\r \n" ); document.write( "\n" ); document.write( "log base b 6=0.9 \n" ); document.write( "log base b 66=3.1 \n" ); document.write( " \n" ); document.write( " |