document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=115041>Question 115041</A>: <I><SPAN STYLE=\"word-break: break-all;\">  I need help solving this equation:\r<BR>\n" );
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document.write( "2(2^2t-5)-4=10 and it says to give approximate answer.. im not real sure how to even start it\r<BR>\n" );
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document.write( " Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83679 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83679\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2(2^(2t-5))-4=10 <BR>\n" );
document.write( "2^(2t-4)= 14<BR>\n" );
document.write( "Take the log of both sides to get:<BR>\n" );
document.write( "(2t-4)log2 = log 14<BR>\n" );
document.write( "2t-4 = [log14]/[log2]<BR>\n" );
document.write( "2t-4 = 3.80735...<BR>\n" );
document.write( "2t = 7.80735...<BR>\n" );
document.write( "t = 3.90368<BR>\n" );
document.write( "=============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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