document.write( "Question 1202146: How many 8 digit numbers can be formed if the leading cannot be a zero and the last number cannot be 1 \n" ); document.write( "
Algebra.Com's Answer #836781 by ikleyn(52814)![]() ![]() You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If repeating is allowed (which I can suppose from the context),\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "then the answer is 9*10*10*10*10*10*10*9 = 81,000,000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Of 8 multipliers, two multipliers of 9 correspond to the first and the last positions, where restrictions are imposed;\r \n" ); document.write( "\n" ); document.write( "six multipliers of 10 correspond to six other positions with no restrictions.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |