document.write( "Question 1202119: Answer the following questions for the function
\n" ); document.write( "f(x)=xx2+4
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\n" ); document.write( "\n" ); document.write( "A. f(x) is concave down on the interval
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\n" ); document.write( "\n" ); document.write( "B. f(x) is concave up on the interval
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\n" ); document.write( "\n" ); document.write( "C. The inflection point for this function is at x= \r
\n" ); document.write( "\n" ); document.write( "D. The minimum for this function occurs at x= \r
\n" ); document.write( "\n" ); document.write( "E. The maximum for this function occurs at x=
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Algebra.Com's Answer #836760 by math_helper(2461) $\"\"$ $\"About$

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document.write( "What is xx2?   Do you mean  ?   If not, please correct and re-post. \r
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document.write( "If you DID MEAN to write  then:\r
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document.write( "f'(x) = 
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document.write( "f\"(x) =    <<< constant positive value so concave up \"everywhere\"
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document.write( "                           which of course includes [-4,6]\r
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document.write( "A.  It is not concave down at all on [-4,6]
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document.write( "B.  It is concave up on [-4,6]
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document.write( "C.  There is no inflection point on [-4,6] (or otherwise)
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document.write( "D.  The minimum is at x=0  (set f' = 0, solve for x)
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document.write( "E.  The maximum on [-4,6] occurs at x=6  (you check at the endpoints of the interval [-4,6]:  f(-4) = 20,   f(6) = 40.  Since no local maximums occur within the interval [-4,6] (rememmber it is concave up so you can only have a local minimum), there are no critical points to check on (-4,6) )\r
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