document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=114983>Question 114983</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x=3y+7<BR>\n" );
document.write( "x+y=-5\r<BR>\n" );
document.write( "\n" );
document.write( "Could someone show me step by step. I am not clear on how to do this yet. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83674 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83674\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since you do not give any directions of how the teacher wants it solved, I will go ahead and solve it by substitution;<BR>\n" );
document.write( "x=3y+7<BR>\n" );
document.write( "x+y=-5<BR>\n" );
document.write( "============<BR>\n" );
document.write( "Since we already have one of the equations solved for x, lets substitute x in the other equation with that;<BR>\n" );
document.write( "(3y+7)+y=-5<BR>\n" );
document.write( "4y+7=-5<BR>\n" );
document.write( "4y=-12<BR>\n" );
document.write( "y=-3<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "now we have what y =, so we can use that in either equation and solve for x;<BR>\n" );
document.write( "x=3(-3)+7<BR>\n" );
document.write( "x=-9+7<BR>\n" );
document.write( "x=-2<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "Let me know if you need it solved another way<BR>\n" );
document.write( ":) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );