document.write( "Question 1202100: A dog trainer has 100 ft of fencing that will be used to create a rectangular work area for dogs. If the trainer wants to enclose an area of 504 ft2, what will be the dimensions of the work area? \n" ); document.write( "
Algebra.Com's Answer #836739 by ikleyn(52800)\"\" \"About 
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\n" ); document.write( "A dog trainer has 100 ft of fencing that will be used to create a rectangular work area for dogs.
\n" ); document.write( "If the trainer wants to enclose an area of 504 ft2, what will be the dimensions of the work area?
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document.write( "L + W should be 100/2 = 50 ft.\r\n" );
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document.write( "So, if x is the width (in feet), then the length is (50-x) ft.\r\n" );
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document.write( "The area equation is\r\n" );
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document.write( "    x*(50-x) = 504\r\n" );
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document.write( "    50x - x^2 = 504\r\n" );
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document.write( "    x^2 - 50x + 504 = 0\r\n" );
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document.write( "Solve using the quadratic formula\r\n" );
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document.write( "    \"x%5B1%2C2%5D\" = \"%2850+%2B-+sqrt%28%28-50%29%5E2+-+4%2A1%2A504%29%29%2F2\" = \"%2850+%2B-+22%29%2F2\".\r\n" );
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document.write( "The roots are  \"x%5B1%5D\" = \"%2850+%2B+22%29%2F2\" = 36  and  \"%2850+-+22%29%2F2\" = 14.\r\n" );
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document.write( "They produce the same rectangle with dimensions 36 ft and 14 ft.    \r\n" );
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document.write( "ANSWER.  The dimensions of the rectangle are 36 ft by 14 ft.\r\n" );
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