document.write( "Question 1200911: A supplier of USB flash claims that more than 11% of the USBs are defective. In a random sample of 167 USBs, it is found that 37 are defective, but the supplier claims that this is only a sample fluctuation. At the 0.05 level of significance, test the supplier's claim that more than 11% are defective. \r
\n" ); document.write( "\n" ); document.write( "a. Is this (a: one sample mean test, b: two sample mean test, c: one proprtion test, d: ch-square test)\r
\n" ); document.write( "\n" ); document.write( "b. Since the test statistic (round to 2 decimals):
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Algebra.Com's Answer #836720 by Theo(13342)\"\" \"About 
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population p = .11
\n" ); document.write( "population q = 1 - .11 = .89
\n" ); document.write( "sample size is 167.
\n" ); document.write( "37 are defective.
\n" ); document.write( "sample p = 37/167 = .2215568862
\n" ); document.write( "standard error of the test is equal to sqrt(population p * population q / 167) = sqrt(.11 * .89 / 167) = .0242121363.
\n" ); document.write( "z-score = (.2215568862 - .11) / .0242121363 = 4.607478034
\n" ); document.write( "area to the right of that = .000002040040862.
\n" ); document.write( "that's significantly less than the critical p-value of .05.
\n" ); document.write( "the probability that the resuls is a fluctuation in smple means is pretty close to 0.
\n" ); document.write( "the conclusion i that the preponderance of the evidence indicates that more than 11% of the USBs are defective, rejecting the claim that it's no more than 11%.\r
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\n" ); document.write( "\n" ); document.write( "this is a one sample proportion test.
\n" ); document.write( "the critical p-value is .05
\n" ); document.write( "the test p-value is 0, rounded to two decimal places.\r
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\n" ); document.write( "\n" ); document.write( "here are the results using the proportion calculator at https://www.statskingdom.com/111proportion_normal1.html\r
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\n" ); document.write( "\n" ); document.write( "differences between the calculator numbers and the ones i calculated have an insignificant impact to the result and are more than likely due to rounding differences.\r
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