document.write( "Question 1202070: Solve for the unknown\r
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Algebra.Com's Answer #836696 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
\"log%281%2F4%2C64%29=n\"---------if hard to read, logarithm base one-fourth, of 64 is n.\r
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\n" ); document.write( "\n" ); document.write( "In exponential form, \"%281%2F4%29%5En=64\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F2%5E2%29%5En=2%5E6\"\r
\n" ); document.write( "\n" ); document.write( "\"%282%5E%28-2%29%29%5En=2%5E6\"\r
\n" ); document.write( "\n" ); document.write( "\"2%5E%28-2n%29=2%5E6\"\r
\n" ); document.write( "\n" ); document.write( "The same base so the exponents must be equal.
\n" ); document.write( "\"-2n=6\"\r
\n" ); document.write( "\n" ); document.write( "\"n=6%2F%28-2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"n=-3\"
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