Algebra.Com's Answer #836663 by Edwin McCravy(20056)![\"\"](\"/images/stars/stars-13.gif\")  
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In the figure below, AXC and BXD are arcs with centers B and A respectively.
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document.write( "ABCD is a square of side 14 cm. Calculate the area of the region CXD.\r
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document.write( "Draw AX and BX.\r\n" );
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document.write( "Triangle ABX is an equilateral triangle because AX = AD = AB and\r\n" );
document.write( "BX = BD = AB, so AX = BX = AB. So angle BAX = 60o.\r\n" );
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document.write( "Area of triangle ABX is     \r\n" );
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document.write( "Angle DAX = 90o - angle XAB = 90o-30o = 60o\r\n" );
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document.write( "Area of sector ADX is   \r\n" );
document.write( "Area of sector BCX is also \r\n" );
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document.write( "Area of square ABCD is   .\r\n" );
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document.write( "Area of region CXD = Area of square - Area of sector ADX - Area of sector BDX - Area of triangle ABX\r\n" );
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document.write( "Area of region CXD =   \r\n" );
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document.write( "That's about 8.594159412 cm2.\r\n" );
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document.write( "Edwin \n" );
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