document.write( "Question 1202039: Given a rectangle with a width of
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document.write( "43
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document.write( " cm and a diagonal
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document.write( "228
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document.write( " cm long, what is its length?\r
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document.write( "Answer: The length is exactly
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document.write( "What is the length to the nearest tenth of a cm?\r
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document.write( "Answer: The length is approximately
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document.write( " cm. \n" );
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Algebra.Com's Answer #836657 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the width, length, and diagonal of the rectangle form a right triangle. \n" ); document.write( "the width of the rectnangle forms the vertical side of the trians which is equal t o 43 centimeter and the diagonal of the rectangle forms the hypotenuse of the triangle which is equal to 228 centimeters.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "by pythagorus, the length squared equals the hypotenuse squared minus the width squared = 228^2 - 43^2 = 50135. \n" ); document.write( "the exact length of the rectangle is sqrt(50135). \n" ); document.write( "the approximate length of the rectamg;e os sqrt(50135) = 223.9084634. \n" ); document.write( "round to the nearest tenth of a centimeter = 223.9. \n" ); document.write( " |