document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1202039>Question 1202039</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given a rectangle with a width of  <BR>\n" );
document.write( "43<BR>\n" );
document.write( "  cm and a diagonal  <BR>\n" );
document.write( "228<BR>\n" );
document.write( "  cm long, what is its length?\r<BR>\n" );
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document.write( "Answer: The length is exactly <BR>\n" );
document.write( "   cm.\r<BR>\n" );
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document.write( "What is the length to the nearest tenth of a cm?\r<BR>\n" );
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document.write( "Answer: The length is approximately <BR>\n" );
document.write( "   cm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #836656 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=836656\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Apply Pytagoras theorem\r<BR>\n" );
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document.write( "l^2+w^2 = diagonal^2\r<BR>\n" );
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document.write( "L^2= diagonal^2-w^2\r<BR>\n" );
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document.write( "L= sqrt(diagonal^2-w^2)\r<BR>\n" );
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document.write( "l= sqrt(228^2-43^2)\r<BR>\n" );
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document.write( "Calculate and round off\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/display-illustration.mpl?tutor=mananth&illustration_name=rectangle.png\">.<BR>\n" );
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