document.write( "Question 1201962: A 2 bowl set has the following description:\r
\n" ); document.write( "\n" ); document.write( "The lid is interchangeable.\r
\n" ); document.write( "\n" ); document.write( "Weight of larger bowl: 12 oz. without lid.\r
\n" ); document.write( "\n" ); document.write( "With lid, larger weighs twice as much as smaller without lid.\r
\n" ); document.write( "\n" ); document.write( "With lid, smaller weighs one third more than larger without lid.\r
\n" ); document.write( "\n" ); document.write( "Calculate weight of lid.\r
\n" ); document.write( "\n" ); document.write( "Let A = larger.\r
\n" ); document.write( "\n" ); document.write( "Let B = smaller.\r
\n" ); document.write( "\n" ); document.write( "Let C = lid.\r
\n" ); document.write( "\n" ); document.write( "A = 12.\r
\n" ); document.write( "\n" ); document.write( "A + C = 2(B).\r
\n" ); document.write( "\n" ); document.write( "A = 1/3(B + C)\r
\n" ); document.write( "\n" ); document.write( "Not sure if set up correctly and how to solve. \n" ); document.write( "

Algebra.Com's Answer #836639 by MathTherapy(10551) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "A 2 bowl set has the following description:\r\n" );
document.write( "\r\n" );
document.write( "The lid is interchangeable.\r\n" );
document.write( "\r\n" );
document.write( "Weight of larger bowl:  12 oz. without lid.\r\n" );
document.write( "\r\n" );
document.write( "With lid, larger weighs twice as much as smaller without lid.\r\n" );
document.write( "\r\n" );
document.write( "With lid, smaller weighs one third more than larger without lid.\r\n" );
document.write( "\r\n" );
document.write( "Calculate weight of lid.\r\n" );
document.write( "\r\n" );
document.write( "Let A = larger.\r\n" );
document.write( "\r\n" );
document.write( "Let B = smaller.\r\n" );
document.write( "\r\n" );
document.write( "Let C = lid.\r\n" );
document.write( "\r\n" );
document.write( "A = 12.\r\n" );
document.write( "\r\n" );
document.write( "A + C = 2(B).\r\n" );
document.write( "\r\n" );
document.write( "A = 1/3(B + C)\r\n" );
document.write( "\r\n" );
document.write( "Not sure if set up correctly and how to solve.\r\n" );
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document.write( "Why did that other person bring in another variable, x? Doesn't the problem list enough variables?\r\n" );
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document.write( "A = 1/3(B + C) <==== This is WRONG!! Read on!\r\n" );
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document.write( "Weight of larger bowl, without lid: A = 12\r\n" );
document.write( "Weight of larger bowl, with lid: A + C, or 12 + C\r\n" );
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document.write( "Weight of smaller bowl, without lid: B\r\n" );
document.write( "Weight of smaller bowl, with lid: B + C\r\n" );
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document.write( "As larger, with lid, weighs twice as much as smaller without lid, we get:  --- eq (i)\r\n" );
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document.write( "    As smaller, with lid, weighs  MORE than larger, without lid, we get: \r\n" );
document.write( "                                                                            -- Substituting 12 for A                                          \r\n" );
document.write( "                                                                           B + C = 16\r\n" );
document.write( "                                                                               B = 16 - C ----- eq (ii)\r\n" );
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document.write( "                                                                   2(16 - C) - C = 12 ---- Substituting 16 - C for B in eq (i)\r\n" );
document.write( "                                                                     32 - 2C - C = 12\r\n" );
document.write( "                                                                        - 2C - C = 12 - 32                                                                        \r\n" );
document.write( "                                                                            - 3C = - 20\r\n" );
document.write( "                                                            Weight of lid, or

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