document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1201995>Question 1201995</A>: <I><SPAN STYLE=\"word-break: break-all;\"> https://ibb.co/svHJWRS<BR>\n" );
document.write( "Solve for a </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #836611 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=836611\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "In the triangle with the 23 degree angle, the second angle measure is 2x, so the measure of the third angle is 180 - (2x+23) = 157-2x.<br><BR>\n" );
document.write( "The exterior angle at that third vertex, with measure 2o, is 23+2x, so o is x+11.5.<br><BR>\n" );
document.write( "Then in the triangle with a as one angle, the measures of the other two angles are x and (157-2x)+(x+11.5).<br><BR>\n" );
document.write( "(x) + (157-2x) + (x+11.5) = 168.5, so a is 180-168.5 = 11.5<br><BR>\n" );
document.write( "ANSWER: 11.5 degrees<br><BR>\n" );
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