document.write( "Question 1201996: Suppose that past history shows that 60% of college students prefer Brand C cola. A sample of 5 students is to be selected. The probability that fewer than 2 prefer brand C is \n" ); document.write( "
Algebra.Com's Answer #836604 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answer: 0.08704
\n" ); document.write( "This value is exact without any rounding done to it.\r
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\n" ); document.write( "\n" ); document.write( "Explanation:\r
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\n" ); document.write( "\n" ); document.write( "n = 5 = sample size
\n" ); document.write( "p = 0.6 = probability of success
\n" ); document.write( "x = number of people, in the sample, who prefer brand C cola
\n" ); document.write( "x is chosen from the set {0,1,2,3,4,5}\r
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\n" ); document.write( "\n" ); document.write( "This is a binomial distribution problem because:
  • There are two outcomes. A person likes the cola or they don't.
  • Each trial is independent of any other. One person doesn't influence another's tastes.
  • The probability someone likes the cola is the same for each trial.
B(x) = binomial probability
\n" ); document.write( "B(x) = (n C x)*(p^x)*(1-p)^(n-x)
\n" ); document.write( "B(x) = (5 C x)*(0.6^x)(1-0.6)^(5-x)
\n" ); document.write( "B(x) = (5 C x)*(0.6^x)(0.4)^(5-x)\r
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\n" ); document.write( "\n" ); document.write( "The nCx notation refers to the nCr formula.
\n" ); document.write( "It is known as the binomial coefficient.\r
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\n" ); document.write( "\n" ); document.write( "Compute the probability of getting x = 0 people who like the cola.
\n" ); document.write( "B(x) = (5 C x)*(0.6^x)(0.4)^(5-x)
\n" ); document.write( "B(0) = (5 C 0)*(0.6^0)(0.4)^(5-0)
\n" ); document.write( "B(0) = 1*(0.6^0)(0.4)^5
\n" ); document.write( "B(0) = 0.01024
\n" ); document.write( "This value is exact without any rounding done to it.\r
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\n" ); document.write( "\n" ); document.write( "Do a similar set of steps for x = 1
\n" ); document.write( "B(x) = (5 C x)*(0.6^x)(0.4)^(5-x)
\n" ); document.write( "B(1) = (5 C 1)*(0.6^1)(0.4)^(5-1)
\n" ); document.write( "B(1) = 5*(0.6^1)*(0.4)^4
\n" ); document.write( "B(1) = 0.0768
\n" ); document.write( "This value is exact without any rounding done to it.\r
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\n" ); document.write( "\n" ); document.write( "The phrasing \"fewer than 2\" means we will add up the results of B(0) and B(1) to get the final answer.
\n" ); document.write( "P(fewer than 2) = B(0) + B(1)
\n" ); document.write( "P(fewer than 2) = 0.01024 + 0.0768
\n" ); document.write( "P(fewer than 2) = 0.08704
\n" ); document.write( "There's an 8.704% chance of getting fewer than 2 people in the sample that like brand C cola.\r
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\n" ); document.write( "\n" ); document.write( "Here are some other binomial distribution problems for more practice.
\n" ); document.write( "https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1201405.html
\n" ); document.write( "https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1201351.html
\n" ); document.write( "https://www.algebra.com/algebra/homework/word/misc/Miscellaneous_Word_Problems.faq.question.1201223.html\r
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\n" ); document.write( "\n" ); document.write( "Further Reading
\n" ); document.write( "https://math.libretexts.org/Bookshelves/Applied_Mathematics/Applied_Finite_Mathematics_(Sekhon_and_Bloom)/09%3A_More_Probability/9.01%3A_Binomial_Probability
\n" ); document.write( "https://www.mathsisfun.com/data/binomial-distribution.html
\n" ); document.write( "https://en.wikipedia.org/wiki/Binomial_coefficient
\n" ); document.write( "https://stattrek.com/online-calculator/binomial
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