document.write( "Question 1201986: An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
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document.write( "Compute the probability of each of the following events.\r
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document.write( "Event A: The sum is greater than 9.
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document.write( "Event B: The sum is divisible by 2 or 3 (or both).\r
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document.write( "Round your answer to 2 decimal places.
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document.write( "(a). P(A) =
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document.write( "(b.) P(B) = \n" );
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Algebra.Com's Answer #836594 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Here the total possible outcomes = 36 n(S) =36\r \n" ); document.write( "\n" ); document.write( "Event (A) (4,6),(5,5),(5,6), (6,4),(6,5),(6,6) n(A) = 6 \n" ); document.write( "P(A) = n(A)/n(S) = 6/36 = 1/6\r \n" ); document.write( "\n" ); document.write( "Event B: The sum is divisible by 2 or 3 (or both). \n" ); document.write( "There are 24 possible outcomes n(B)=24 \n" ); document.write( "P(B)= n(B)/n(S)= 24/36= 2/3\r \n" ); document.write( "\n" ); document.write( "Convert to percent if required\r \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |