document.write( "Question 1201967: The hypotenuse, c, of right angle ABC is 10.2 cm long. Given the trigonometric ratio sec(A) = 15/3 for angle A, what is the area of the triangle to the nearest tenth of a cm^2? \n" ); document.write( "
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\n" ); document.write( "The hypotenuse, c, of right angle ABC is 10.2 cm long. Given the trigonometric ratio sec(A) = 15/3 for angle A, what is the area of the triangle to the nearest tenth of a cm^2?\r
\n" ); document.write( "\n" ); document.write( "Sec A =15/3 =5:1\r
\n" ); document.write( "\n" ); document.write( "cos A = AB/AC =1/5\r
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\n" ); document.write( "\n" ); document.write( "1/5 = AB/10.2
\n" ); document.write( "AB= 2.04 cm\r
\n" ); document.write( "\n" ); document.write( "BC calculate by Pythagoras Theorem\r
\n" ); document.write( "\n" ); document.write( "sqrt(10.2^2-2.04^2)= 9.999\r
\n" ); document.write( "\n" ); document.write( "Area of triangle = 1/2 *B * h
\n" ); document.write( "1/2 * 9.999 *2.04 = 10.198 cm^2 ( you round off)\r
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