document.write( "Question 115021: I'm not sure how to do this one. Can you please help me with it?\r
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\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 2 meters longer than the width. If the area is 10 square meters, find the rectangle's dimensions. Round to the nearest tenth of a meter. \n" ); document.write( "
Algebra.Com's Answer #83656 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
L=W+2
\n" ); document.write( "10=L*W
\n" ); document.write( "10=(W+2)W
\n" ); document.write( "10=W^2+2W
\n" ); document.write( "W^2+2W-10=0
\n" ); document.write( "USING THE QUADRATIC EQUATION WE GET:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "W=(-2+-SQRT[2^2-4*1*-10])/2*1
\n" ); document.write( "W=(-2+-SQRT[4+40])/2
\n" ); document.write( "W=(-2+-SQRT44)/2
\n" ); document.write( "W=(-2+-6.633)/2
\n" ); document.write( "W=-2+6.633)/2
\n" ); document.write( "W=4.633/2
\n" ); document.write( "W=2.3165 ANSWER FOR THE WIDTH.
\n" ); document.write( "L=2.3165+2=4.3165 ANSWER FOR THE LENGTH.
\n" ); document.write( "PROOF
\n" ); document.write( "2.3165*4.3165=10
\n" ); document.write( "10~10
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