document.write( "Question 1201947: Choose a student in grades 9 to 12 at random and ask if he or she is studying a language other than English. Here is the distribution of the students:
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\n" ); document.write( "Probability 0.22 0.1 0.04 0.01 0.63
\n" ); document.write( "(a) What is the probability that a randomly chosen student is, in fact, studying a language other than English?
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\n" ); document.write( "\n" ); document.write( "(b) What is the probability that a randomly chosen student is studying French, German, or Spanish?
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\n" ); document.write( "\n" ); document.write( "(c) What is the probability that a randomly chosen student is studying a language besides English, but not German?
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Algebra.Com's Answer #836558 by ikleyn(52778)\"\" \"About 
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document.write( "(a)  To answer (a),  add the given numbers from 0.22 to 0.63, inclusive.\r\n" );
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document.write( "     Make sure that the sum is 1, or 100%.  So, the answer to (a) is  P = 1, or 100%.\r\n" );
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document.write( "     It means that the sets of students, learning the above mentioned languages,\r\n" );
document.write( "     are disjoint and cover the entire set of students in grades 9 to 12.\r\n" );
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document.write( "(b)  It implies that P(French) = 0.1;  P(German) = 0.04;  P(Spanish) = 0.22.     ANSWER\r\n" );
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document.write( "(c)  P(not German) = 1 - 0.04 = 0.96, or 96%.    ANSWER\r\n" );
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