document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1201954>Question 1201954</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle whose length is twice as long as its width is inscribed in a circle of area π. What is the area of the rectangle?\r<BR>\n" );
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document.write( "(A) 2/5<BR>\n" );
document.write( "(B) 4/5<BR>\n" );
document.write( "(C) 8/5<BR>\n" );
document.write( "(D) 5/4<BR>\n" );
document.write( "(E) 5/8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #836546 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=836546\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let  x be width then 2x =length\r<BR>\n" );
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document.write( "Are of circle = pi*r^2<BR>\n" );
document.write( "pi=pir^2\r<BR>\n" );
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document.write( "r^2=1\r<BR>\n" );
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document.write( "r=1 <BR>\n" );
document.write( "d=2 \r<BR>\n" );
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document.write( "Apply pythagoras theorem in triangle<BR>\n" );
document.write( "x^2+(2x)^2 = 2^2\r<BR>\n" );
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document.write( "5x^2=4<BR>\n" );
document.write( "x^2= 4/5<BR>\n" );
document.write( "x=(2)/sqrt(5)\r<BR>\n" );
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document.write( "width = (2)/sqrt(5)<BR>\n" );
document.write( "length = 4/sqrt(5)<BR>\n" );
document.write( "Area of rectangle = 2 * area of triangle\r<BR>\n" );
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document.write( "Area of rectangle  = 2* 1/2 * 2/sqrt(5) * 4/sqrt(5)\r<BR>\n" );
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document.write( "=8/5\r<BR>\n" );
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document.write( " </SPAN>\n" );
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