document.write( "Question 1201940: How many four-digit numbers can be formed from the digits 0, 1,2,3,4,5,and 6 if each digit can be used only once?
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document.write( "(b) How many of these are odd numbers?
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document.write( "(c)How many are greater than 330? \n" );
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Algebra.Com's Answer #836530 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(a) Total number of 4-digit numbers \n" ); document.write( "There is one restriction: 0 can't be the first digit \n" ); document.write( "6 choices for the first digit (1 to 6) \n" ); document.write( "6 choices for the second (any of the remaining 6 digits, including 0) \n" ); document.write( "5 choices for the third \n" ); document.write( "4 choices for the fourth \n" ); document.write( "ANSWER for (a): 6*6*5*4 = 720 \n" ); document.write( "(b) Number of 4-digit odd numbers \n" ); document.write( "There are two restrictions: 0 can't be first, and the last digit must be odd. There are two cases to consider -- first digit odd or first digit even. \n" ); document.write( "(b1) odd; first digit even \n" ); document.write( "3 choices for first digit (2, 4, or 6) \n" ); document.write( "3 choices for the last digit (1, 3, or 5) \n" ); document.write( "5 choices for the second (any of the remaining 5 digits) \n" ); document.write( "4 choices for the third \n" ); document.write( "total: 3*3*5*4 = 180 \n" ); document.write( "(b2) odd, first digit odd \n" ); document.write( "3 choices for the first digit (1, 3, or 5) \n" ); document.write( "2 choices for the last (there are only 2 other odd digits) \n" ); document.write( "5 choices for the second (any of the remaining 5 digits) \n" ); document.write( "4 choices for the third \n" ); document.write( "total: 3*2*5*4 = 120 \n" ); document.write( "ANSWER for (b): 180+120 = 300 \n" ); document.write( "(c) Number greater than 330 \n" ); document.write( "ANSWER: 720 (all 4-digit numbers are greater than 330...!) \n" ); document.write( "NOTE: The \"330\" in the post is probably a typo; it was probably supposed to be a 4-digit number. So this was probably supposed to be a much more interesting problem -- but I am answering the question that was asked in the post.... \n" ); document.write( "NOTE: For a student just learning to work problems like this, it is a useful exercise to calculate how many of these 4-digit numbers are even. Since there are a total of 720 numbers, of which 300 are odd, there should be 420 that are even. \n" ); document.write( "Let's see.... \n" ); document.write( "(d1) even, first digit even \n" ); document.write( "3 choices for the first digit (2, 4, or 6) \n" ); document.write( "3 choices for the last digit (any of the three remaining even digits, including 0) \n" ); document.write( "5 choices for the second \n" ); document.write( "4 choices for the third \n" ); document.write( "total: 3*3*5*4 = 180 \n" ); document.write( "(d2) even, first digit odd \n" ); document.write( "3 choices for the first digit (1, 3, or 5) \n" ); document.write( "4 choices for the last digit (any of the 4 even digits) \n" ); document.write( "5 choices for the second \n" ); document.write( "4 choices for the third \n" ); document.write( "total: 3*4*5*4 = 240 \n" ); document.write( "Total even: 180+240 = 420 CORRECT! \n" ); document.write( " \n" ); document.write( " |