document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1201910>Question 1201910</A>: <I><SPAN STYLE=\"word-break: break-all;\"> cot(arccos-square root 6/3)\r<BR>\n" );
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document.write( "I know triangle is in quadrant II because of negative sign.\r<BR>\n" );
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document.write( "Just confused on how the answer is -square root 2.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #836487 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=836487\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The range of the arccos function is from 0 to pi (radians), or 0 to 180 degrees, so the angle is in quadrant I or II.<br><BR>\n" );
document.write( "Then, since the cosine is negative, the angle is in quadrant II.<br><BR>\n" );
document.write( "You have gotten that far in your work.<br><BR>\n" );
document.write( "From there, you can use <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sin%5E2%28x%29%2Bcos%5E2%28x%29=1 ALIGN=MIDDLE  ALT=\"sin%5E2%28x%29%2Bcos%5E2%28x%29=1\"   DISABLED_style= \"max-width:90%; height:auto;\" > to find the sine of the angle, choosing the positive answer because the angle is in quadrant II, where sine is positive.<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sin%5E2%28x%29%2B%28-sqrt%286%29%2F3%29%5E2=1 ALIGN=MIDDLE  ALT=\"sin%5E2%28x%29%2B%28-sqrt%286%29%2F3%29%5E2=1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sin%5E2%28x%29%2B6%2F9=1 ALIGN=MIDDLE  ALT=\"sin%5E2%28x%29%2B6%2F9=1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sin%5E2%28x%29=1%2F3 ALIGN=MIDDLE  ALT=\"sin%5E2%28x%29=1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sin%28x%29=1%2Fsqrt%283%29=sqrt%283%29%2F3 ALIGN=MIDDLE  ALT=\"sin%28x%29=1%2Fsqrt%283%29=sqrt%283%29%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "Then use <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cot%28x%29=cos%28x%29%2Fsin%28x%29 ALIGN=MIDDLE  ALT=\"cot%28x%29=cos%28x%29%2Fsin%28x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > to find the answer to the problem.<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cot%28x%29=%28-sqrt%286%29%2F3%29%2F%28sqrt%283%29%2F3%29=-sqrt%286%29%2Fsqrt%283%29=-sqrt%282%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
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