document.write( "Question 1201890: Find three consecutive odd integers such that four times the sum of the first and second is 11 more than 3 times the third. \n" ); document.write( "

Algebra.Com's Answer #836445 by Edwin McCravy(20054) $\"\"$ $\"About$

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Find three consecutive odd integers...

1st odd integer = x\r\n" );
document.write( "2nd odd integer = x+2\r\n" );
document.write( "3rd odd integer = x+4

such that four times the sum of the first and second

4[x + (x+2)]\r\n" );
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document.write( "is \r\n" );
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document.write( "   =

11 more than 3 times the third.

3(x+4) + 11\r\n" );
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document.write( "4[x + (x+2)] = 3(x+4) + 11\r\n" );
document.write( "4[x + x + 2] = 3x + 12 + 11\r\n" );
document.write( "   4[2x + 2] = 3x + 23\r\n" );
document.write( "      8x + 8 = 3x + 23\r\n" );
document.write( "          5x = 15\r\n" );
document.write( "           x = 3\r\n" );
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document.write( "1st odd integer = x = 3\r\n" );
document.write( "2nd odd integer = x+2 = 3+2 = 5\r\n" );
document.write( "3rd odd integer = x+4 = 3+4 = 7\r\n" );
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document.write( "Checking:

four times the sum of the first and second

4(3 + 5) = 4(8) = 32

is 11 more than 3 times the third.

3(7) + 11 = 21 + 11 = 32\r\n" );
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document.write( "So it checks.\r\n" );
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document.write( "Edwin

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