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document.write( "A ball is given an initial velocity of 10.0 m/s at 37° above the horizontal.
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document.write( "Assume that the ball landed at the same height.\r
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document.write( "a. Calculate the horizontal and vertical components of the ball’s initial velocity.
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document.write( "b. Calculate the total time of the ball.
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document.write( "c. Calculate the range and maximum height of the ball.
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document.write( "(a) the horizontal component is
= 10*cos(37°) = 10*0.7986 = 7.986 m/s.\r\n" );
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document.write( " Horizontal component of velocity remains the same, with no change,\r\n" );
document.write( " during the entire flight until landing.\r\n" );
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document.write( " Vertical component of the initial velocity is
= 10*sin(37°) = 10*0.6018 = 6.018 m/s.\r\n" );
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document.write( "(b) With the found vertical initial velocity in (a), the algebraic function for the height is\r\n" );
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document.write( " h(t) =
=
. (1)\r\n" );
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document.write( " Equation to find the time of landing is\r\n" );
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=
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document.write( " After canceling
in both sides, this equation takes the form\r\n" );
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= 0,\r\n" );
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document.write( " (-4.9t + 6.018)*t = 0\r\n" );
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document.write( " and gives the value for the time of landing t =
= 1.228 of a second.\r\n" );
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document.write( " So, the ball flights during 1.228 seconds.\r\n" );
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document.write( "(c) Half of this time,
= 0.614 of a second, the ball is on ascending trajectory.\r\n" );
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document.write( " Second half, or 0.614 of a second, the ball is on descending trajectory.\r\n" );
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document.write( " To find the range (the horizontal distance), multiply the horizontal component of the velocity \r\n" );
document.write( " by the flight time\r\n" );
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document.write( " the range = 7.986*1.228 = 9.807 m (rounded).\r\n" );
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document.write( " To find the maximum height, find the maximum of this quadratic function (1) (see above).\r\n" );
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document.write( " As I just said, during 0.614 of a second the ball moves up, so substitute t= 0.614 s\r\n" );
document.write( " into the function.\r\n" );
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document.write( " Doing this way, you will find the maximum height over
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=
= 1.85 m (rounded).\r\n" );
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document.write( "Solved.\r
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document.write( "I answered all your questions.\r
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