document.write( "Question 1201833: Introduce variables and write two equations
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\n" ); document.write( "A collection of dimes and quarters is worth $15.25. There are 103 coins in total. How many of each kind of coin is there?
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Algebra.Com's Answer #836365 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answer:
\n" ); document.write( "70 dimes
\n" ); document.write( "33 quarters
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\n" ); document.write( "\n" ); document.write( "70 dimes + 33 quarters = 70*10 + 33*25 = 1525 cents = 15.25 dollars\r
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\n" ); document.write( "\n" ); document.write( "Work Shown:\r
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\n" ); document.write( "\n" ); document.write( "d = number of dimes
\n" ); document.write( "q = number of quarters
\n" ); document.write( "These variables are placeholders for nonnegative whole numbers 0,1,2,3,...\r
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\n" ); document.write( "\n" ); document.write( "d+q = 103 coins total
\n" ); document.write( "q = 103-d
\n" ); document.write( "It will be used in a substitution step later\r
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\n" ); document.write( "\n" ); document.write( "10d = value of the dimes only (cents)
\n" ); document.write( "25q = value of the quarters only (cents)
\n" ); document.write( "10d+25q = total value (cents)
\n" ); document.write( "10d+25q = 1525
\n" ); document.write( "10d+25( q ) = 1525
\n" ); document.write( "10d+25( q ) = 1525
\n" ); document.write( "10d+25( 103-d ) = 1525 ... substitution
\n" ); document.write( "10d+25*103+25*(-d) = 1525
\n" ); document.write( "10d+2575-25d = 1525
\n" ); document.write( "-15d+2575 = 1525
\n" ); document.write( "-15d = 1525-2575
\n" ); document.write( "-15d = -1050
\n" ); document.write( "d = -1050/(-15)
\n" ); document.write( "d = 70 dimes\r
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\n" ); document.write( "\n" ); document.write( "q = 103-d
\n" ); document.write( "q = 103-70
\n" ); document.write( "q = 33 quarters\r
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\n" ); document.write( "\n" ); document.write( "Another approach:\r
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\n" ); document.write( "\n" ); document.write( "The 25 cents in $15.25 tells us that there's at least one quarter.
\n" ); document.write( "It is impossible to reach this subtotal amount with dimes alone.\r
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\n" ); document.write( "\n" ); document.write( "If we had 1 quarter and 103-1 = 102 dimes, then we have:
\n" ); document.write( "1 quarter + 102 dimes = 1*25 + 102*10 = 1045 cents = $10.45
\n" ); document.write( "We come up short of the goal $15.25\r
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\n" ); document.write( "\n" ); document.write( "Let's replace 1 dime with 1 quarter.
\n" ); document.write( "Difference in coin value = 25-10 = 15 cents
\n" ); document.write( "Each time we do this replacement of \"1 dime for 1 quarter\", the total value goes up by 15 cents aka $0.15
\n" ); document.write( "This is the net change.\r
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\n" ); document.write( "\n" ); document.write( "Because we want the $10.45 to go to $15.25, we must increase by $4.80
\n" ); document.write( "(since 15.25-10.45 = 4.80 )\r
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\n" ); document.write( "\n" ); document.write( "n = number of increases of 15 cents each
\n" ); document.write( "0.15n = total increase needed
\n" ); document.write( "0.15n = 4.80
\n" ); document.write( "n = 4.80/0.15
\n" ); document.write( "n = 32
\n" ); document.write( "We need 32 increases of 15 cents each to go from $10.45 to $15.25
\n" ); document.write( "Meaning we need to do the replacement of \"1 dime for 1 quarter\" a total of 32 times.\r
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\n" ); document.write( "\n" ); document.write( "Add 32 to the quarter count, and subtract 32 from the dime count.
\n" ); document.write( "1+32 = 33 quarters
\n" ); document.write( "102-32 = 70 dimes
\n" ); document.write( "which are the final answers.\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "70 dimes + 33 quarters
\n" ); document.write( "= 70*10 + 33*25
\n" ); document.write( "= 700 cents + 825 cents
\n" ); document.write( "= 1525 cents
\n" ); document.write( "= 1525/100
\n" ); document.write( "= 15.25 dollars
\n" ); document.write( "The answers are confirmed.
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