document.write( "Question 1201829: A theater group made appearances in two cities. The hotel charge before tax in the second city was $500 higher than in the first. The tax in the first city was 7%, and the tax in the second city was 8%. The total hotel tax paid for the two cities was $865. How much was the hotel charge in each city before tax?
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Algebra.Com's Answer #836354 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answer:
\n" ); document.write( "first hotel's price before tax = $5500
\n" ); document.write( "second hotel's price before tax = $6000\r
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\n" ); document.write( "\n" ); document.write( "Work Shown:\r
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\n" ); document.write( "\n" ); document.write( "x = first hotel price before tax
\n" ); document.write( "x+500 = second hotel price before tax\r
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\n" ); document.write( "\n" ); document.write( "7% of x = 0.07x = tax amount for first hotel
\n" ); document.write( "8% of x+500 = 0.08(x+500) = 0.08x+40 = tax amount for second hotel\r
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\n" ); document.write( "\n" ); document.write( "Combine the two tax amounts and we'll get $865
\n" ); document.write( "tax1 + tax2 = 865
\n" ); document.write( "(0.07x) + (0.08x+40) = 865
\n" ); document.write( "0.15x+40 = 865
\n" ); document.write( "0.15x = 865-40
\n" ); document.write( "0.15x = 825
\n" ); document.write( "x = 5500
\n" ); document.write( "then
\n" ); document.write( "x+500 = 5500+500 = 6000
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