document.write( "Question 114934: Alexandra lives 33 miles from work. During the summer she rides her bike at 7mph to the metro station. She then takes the metro to work which travels at 39mph.
\n" ); document.write( "If she spends 21 min more on the bike than on the metro,what is the distance from her house to the metro?(work with time in hours and round your answer to a whole number. \r
\n" ); document.write( "\n" ); document.write( "Here is what I have tried: the total distance is 33 miles from home to work. The distance from home to the metro is 33-x. THe time x +.35 hr.= TIME ON THE METRO, I think. I tried 7(x)+39(x+.35
\n" ); document.write( " 7x╬lus 39x plus 13.65equals33 x equals .42 hr that is the time biking 7x.42equals 2.94 miles. round to 3 miles.Is this right \n" ); document.write( "

Algebra.Com's Answer #83633 by edjones(8007) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "st=d t=time (hrs) s=speed d=distance
\n" ); document.write( ".
\n" ); document.write( "Let t be time on the metro.
\n" ); document.write( "7(t+.35)+39t=33
\n" ); document.write( "7t+2.45+39t=33
\n" ); document.write( "46t=33-2.45
\n" ); document.write( "46t=30.55
\n" ); document.write( "t=.66413 hrs time on metro
\n" ); document.write( "t+.35=1.01413 hrs on the bike
\n" ); document.write( "1.01413*7=7 mi from her house to the metro station.
\n" ); document.write( ".
\n" ); document.write( "Check:
\n" ); document.write( ".66413*39=26
\n" ); document.write( "26+7=33
\n" ); document.write( ".
\n" ); document.write( "Ed \n" ); document.write( "

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