document.write( "Question 114919: Patti needs 8000 litres of a 35% solution of hydrogen chloride. How many litres of a 40% solution and how many litres of a 20% solution will she use?\r
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document.write( "1. How many litres of 40% solution & how many solutions of 20% solution?
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document.write( "2. Litre of 40% = x
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document.write( " Litre of 20% = y\r
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document.write( "x + y = 8000
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document.write( ".40x + .20y = .35\r
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document.write( "Many thanks for any assistance your able to share.
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document.write( "pmoss
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document.write( "From this point on I'm stuck..I don't know how to solve the problem. \n" );
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Algebra.Com's Answer #83632 by rajagopalan(174)![]() ![]() You can put this solution on YOUR website! Note * is used as multiplication symbol as x is used as the variable: \n" ); document.write( ".. \n" ); document.write( "Let Litres of 40% = x \n" ); document.write( "Then Litres of 20% = (8000-x)\r \n" ); document.write( "\n" ); document.write( "But Total H Cl in 8000 litres of 35% solution = 0.35*8000= 2800 litres\r \n" ); document.write( "\n" ); document.write( "H Cl in 40% solution =0.4*x \n" ); document.write( "H Cl in 20% solution =0.2*(8000-x)\r \n" ); document.write( "\n" ); document.write( "Now our equation is (0.4*x)+(0.2*(8000-x))=2800 \n" ); document.write( "0.4x+(8000-x)0.2=2800 \n" ); document.write( "0.4x-1600-0.2x=2800 \n" ); document.write( "0.2x-1600=2800 \n" ); document.write( "0.2x=2800-1600 \n" ); document.write( "0.2x=1200 \n" ); document.write( "x=1200/0.2=6000\r \n" ); document.write( "\n" ); document.write( "so 40% solution = 6000 litres \n" ); document.write( "and 20% solution =2000 litres\r \n" ); document.write( "\n" ); document.write( "Okay\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |