document.write( "Question 1201801: Based on historical data, your manager believes that 28% of the company's orders come from first-time customers. A random sample of 151 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is between 0.22 and 0.43?\r
\n" ); document.write( "\n" ); document.write( "Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations.
\n" ); document.write( "

Algebra.Com's Answer #836306 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Answer: 0.9497 (approximate)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "================================================================\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Explanation:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I'm not familiar with wamap, so I won't be much help there. But I can help with the rest.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Given info:
\n" ); document.write( "\"Based on historical data, your manager believes that 28% of the company's orders come from first-time customers\"
\n" ); document.write( "This leads to p = 0.28 as the population proportion. We convert from percent form to decimal form. Move the decimal 2 spots to the left.
\n" ); document.write( "The value of p is always between 0 and 1 inclusive, ie \"0+%3C=+p+%3C=+1\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "More given info:
\n" ); document.write( "\"A random sample of 151 orders will be used to estimate the proportion of first-time-customers.\"
\n" ); document.write( "meaning
\n" ); document.write( "n = 151 = sample size\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Summary so far
\n" ); document.write( "p = 0.28 = population proportion
\n" ); document.write( "n = 151 = sample size\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now we look at the phat distribution.
\n" ); document.write( "Sometimes it is spelled out as \"p-hat\"
\n" ); document.write( "It's named as such because it is the letter p with a small hat on top.
\n" ); document.write( "phat = \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "That font is probably a bit distorted, so here's a link that might offer a better image
\n" ); document.write( "https://tex.stackexchange.com/questions/250466/vector-with-boldface-and-a-hat-on-top\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The phat is the sample proportion.
\n" ); document.write( "phat's job is to estimate p.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The phat distribution has these 2 properties
  • mean = p
  • standard deviation = standard error = sqrt(p*(1-p)/n)
I'll use \"SE\" as the abbreviation of \"standard error\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In this case, we have
  • mean = 0.28
  • SE = sqrt(0.28*(1-0.28)/151) = 0.036539 approximately
We can use a normal distribution with these two parameters.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The goal is to compute P(0.22 < phat < 0.43)
\n" ); document.write( "It gives the probability the sample proportion phat is between 0.22 and 0.43 \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let's compute the z score when phat = 0.22
\n" ); document.write( "z = (phat - p)/SE
\n" ); document.write( "z = (0.22 - 0.28)/0.036539
\n" ); document.write( "z = -1.64208106406853
\n" ); document.write( "z = -1.6421\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Repeat for phat = 0.43
\n" ); document.write( "z = (phat - p)/SE
\n" ); document.write( "z = (0.43 - 0.28)/0.036539
\n" ); document.write( "z = 4.10520266017132
\n" ); document.write( "z = 4.1052\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The task of computing
\n" ); document.write( "P(0.22 < phat < 0.43)
\n" ); document.write( "is roughly equivalent to
\n" ); document.write( "P(-1.6421 < z < 4.1052)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now use a calculator such as this one
\n" ); document.write( "https://davidmlane.com/normal.html
\n" ); document.write( "or something like a TI83 or TI84\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Or you could use a table like this
\n" ); document.write( "https://www.ztable.net/
\n" ); document.write( "The drawback with the table is you must round each z score to 2 decimal places. Thereby losing accuracy.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I'll go with the calculator approach. I'll assume the calculator you're using is similar to the one in the link.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You should find that
\n" ); document.write( "P(-1.6421 < z < 4.1052) = 0.9497
\n" ); document.write( "which leads back to
\n" ); document.write( "P(0.22 < phat < 0.43) = 0.9497
\n" ); document.write( "This value is approximate.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If we randomly picked phat values from the phat distribution, then there's roughly a 94.97% chance of getting a phat in the interval 0.22 < phat < 0.43
\n" ); document.write( "phat = sample proportion
\n" ); document.write( "
\n" ); document.write( "
\n" );