document.write( "Question 1201763: In a survey sample of 83 respondents, about 30.1% of the sample work less than 40 hr per week. What is the estimated standard error of the proportion for this group? \n" ); document.write( "
Algebra.Com's Answer #836269 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "n = 83 = sample size \n" ); document.write( "phat = 0.301 = sample proportion\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "SE = standard error of the proportion \n" ); document.write( "SE = sqrt(phat*(1-phat)/n) \n" ); document.write( "SE = sqrt(0.301*(1-0.301)/83) \n" ); document.write( "SE = 0.0503480656 \n" ); document.write( "That value is approximate. \n" ); document.write( "Round it however needed. \n" ); document.write( " \n" ); document.write( " |