document.write( "Question 1201763: In a survey sample of 83 respondents, about 30.1% of the sample work less than 40 hr per week. What is the estimated standard error of the proportion for this group? \n" ); document.write( "
Algebra.Com's Answer #836269 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "n = 83 = sample size
\n" ); document.write( "phat = 0.301 = sample proportion\r
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\n" ); document.write( "\n" ); document.write( "SE = standard error of the proportion
\n" ); document.write( "SE = sqrt(phat*(1-phat)/n)
\n" ); document.write( "SE = sqrt(0.301*(1-0.301)/83)
\n" ); document.write( "SE = 0.0503480656
\n" ); document.write( "That value is approximate.
\n" ); document.write( "Round it however needed.
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