document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1201760>Question 1201760</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the lateral area of a cylinder is four times the area of its base. What is the height of the cylinder in terms of its radius<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #836259 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=836259\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r, radius of base, same as radius of cylinder\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, base area\r<BR>\n" );
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document.write( "If h is height of cylinder, description gives <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi%2Ar%2Ah=4pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"2pi%2Ar%2Ah=4pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and you can solve for h.\r<BR>\n" );
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document.write( "Further Review:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi%2Ar ALIGN=MIDDLE  ALT=\"2pi%2Ar\"   DISABLED_style= \"max-width:90%; height:auto;\" >, the distance around the cylinder<BR>\n" );
document.write( "h, the length of the cylinder<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi%2Ar%2Ah ALIGN=MIDDLE  ALT=\"2pi%2Ar%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" >, the lateral area of the cylinder.\r<BR>\n" );
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document.write( "You were given that this lateral area is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2Api%2Ar%5E2 ALIGN=MIDDLE  ALT=\"4%2Api%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Also according to description,  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi%2Ar%2Ah=4%2Api%2Ar%5E2 ALIGN=MIDDLE  ALT=\"2pi%2Ar%2Ah=4%2Api%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "SOLVE FOR h.  That is the answer to the question!  Do this correctly, and the result will match one of your choices.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi%2Ar%2Ah=4pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"2pi%2Ar%2Ah=4pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F%282pi%2Ar%29%292pi%2Ar%2Ah=%281%2F%282pi%2Ar%29%294pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"%281%2F%282pi%2Ar%29%292pi%2Ar%2Ah=%281%2F%282pi%2Ar%29%294pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F%282pi%2Ar%29%292pi%2Ar%2Ah=%281%2F%282pi%2Ar%29%292%2A2pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"%281%2F%282pi%2Ar%29%292pi%2Ar%2Ah=%281%2F%282pi%2Ar%29%292%2A2pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F%28cross%282pi%2Ar%29%29%29cross%282pi%2Ar%29%2Ah=%281%2F%28cross%282pi%2Ar%29%29%292%2Across%282pi%2Ar%29%2Ar ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "You understand how this works? </SPAN>\n" );
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