document.write( "Question 1201743:  Hi
\n" );
document.write( "a container has a rectangular base with a length twice its breadth. Its height is 30cm. It is 1/3 full. 3000cm^2 of water is then added and the new height is 25cm.\r
\n" );
document.write( "\n" );
document.write( "1) How much more water is needed to fill the tank to its brim\r
\n" );
document.write( "\n" );
document.write( "2) what is the length of the container.\r
\n" );
document.write( "\n" );
document.write( "Thanks \n" );
document.write( "
| Algebra.Com's Answer #836245 by greenestamps(13209)     You can put this solution on YOUR website! \n" ); document.write( "I think we can call the \"3000 cm^2\" in the problem a typographical error instead of a fatal flaw. Obviously the intent was 3000 cm^3.... \n" ); document.write( "The height is 30cm, and initially the tank is 1/3 full, so it is filled to a depth of 10cm. \n" ); document.write( "When 3000 cm^3 of water is added, the depth of water in the tank becomes 25cm, a change of 15cm. Since the change in the depth of the water is half the height of the tank, the 3000 cm^3 that was added is half the volume of the tank. So the volume of the tank is 6000 cm^3. \n" ); document.write( "1) How much more water is needed to fill the tank to its brim? \n" ); document.write( "The water is now 5cm from the top of the tank. Since adding 3000 cm^3 raised the depth of the water by 15cm, the additional amount of water needed to raise the depth of the water another 5cm is one-third of 3000 cm^3, or 1000 cm^3. \n" ); document.write( "ANSWER: 1000 cm^3 \n" ); document.write( "2) what is the length of the container? \n" ); document.write( "The volume of the tank is 6000 cm^3, and the height is 30cm; that means the area of the rectangular base is 200 cm^2. Then, since the length is twice the width, the length of the base is 20cm and the width is 10cm. \n" ); document.write( "ANSWER: 20cm \n" ); document.write( " \n" ); document.write( " |