document.write( "Question 1201709: The sample mean (n = 175) for student housing is $616.91 and the sample standard deviation is $128.65. Construct a 95% confidence interval and evaluate for $650. \n" ); document.write( "
Algebra.Com's Answer #836196 by Theo(13342)\"\" \"About 
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sample mean is 616.91
\n" ); document.write( "sample standard deviation is 128.65
\n" ); document.write( "sample size is 175
\n" ); document.write( "standard error = standard deviation / square root of sample size = 128.65/sqrt(175) = 9.725025891.
\n" ); document.write( "t-score is used, rather than z-score.
\n" ); document.write( "since the sample size is so large, the difference between using the t-score or the z-score will be small.
\n" ); document.write( "t-score 95% confidence interval with 174 degrees of freedom is t = plus or minus 1.9736914.
\n" ); document.write( "use the t-score formula to find the equivalent raw scores.
\n" ); document.write( "t-score formula is t = (x - m) / s
\n" ); document.write( "in this problem, t is the critical t-score, x is the critical raw score, m is the sample mean, s is the standard error.
\n" ); document.write( "on the low side, you get -1.9736914 = (x - 616.91) / 9.72502591.
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = -1.9736914 * 9.72502591 + 616.91 = 597.7158.
\n" ); document.write( "on the high side, you get 1.9736914 = (x - 616.91) / 9.72502591.
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = 1.9736914 * 9.72502591 + 616.91 = 636.1042.
\n" ); document.write( "your 95% confidence interval is from 597.7158 to 636.1042.
\n" ); document.write( "evaluating a raw score of 650 is done in the folllowig manner.
\n" ); document.write( "use the t-score formula to get:
\n" ); document.write( "t = (x - m) / s becomes t = (650 - 616.91) / 9.72502591 = 3.402561636.
\n" ); document.write( "area to the right of t-score, with 174 degrees of freedom = .0004141885659.
\n" ); document.write( "since that is considerably less than the 95% confidence interval alpha on the high end of .025, the results are considered significant.
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