document.write( "Question 1201701: The equation of a parabola is 12 y = ( x − 1 ) 2 − 48 12y=(x-1)2-48 . Identify the vertex, focus, and directrix of the parabola. \n" ); document.write( "
Algebra.Com's Answer #836193 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "******************** \n" ); document.write( "NOTE for future reference: the symbol \"^\" (shift-6) is commonly used to represent exponents. So you can write the equation for this problem as \n" ); document.write( "12y=(x-1)^2-48 \n" ); document.write( "******************* \n" ); document.write( "The x term is squared, so the graph opens up or down. The general vertex form of the equation of a parabola I prefer to use is this: \n" ); document.write( " \n" ); document.write( "Note many references will show this equation in different equivalent forms; and different students have different preferences on which form to use. Some common equivalent forms are \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "In any of those forms, the vertex is (h,k); p is the directed distance (i.e., can be negative) from the directrix to the vertex and from the vertex to the focus. \n" ); document.write( "Put the equation in your example in this form: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The vertex is (1,-4) and p is 3. \n" ); document.write( "The directrix is p = 3 units below the vertex, at y = -7. \n" ); document.write( "The focus is p = 3 units above the vertex, at (1,-1). \n" ); document.write( "ANSWERS: \n" ); document.write( "vertex (1,-4) \n" ); document.write( "focus (1,-1) \n" ); document.write( "directrix y = -7 \n" ); document.write( " \n" ); document.write( " |