document.write( "Question 1201706: A closet contains 5 short-sleeve shirts and 3 long-sleeve shirts. Two shirts are chosen from the closet without looking. What is the probability that both shirts have short sleeves? \n" ); document.write( "
Algebra.Com's Answer #836191 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "A student just learning about probability should be able to solve this problem by both of two basic probability methods.

\n" ); document.write( "(1) Pick one shirt at a time....

\n" ); document.write( "When picking the first shirt, there are 8 shirts, of which 5 are short sleeve. The probability of getting a short-sleeve shirt on the first pick is 5/8.

\n" ); document.write( "When picking the second shirt, there are 7 shirts left, of which 4 are short sleeve. The probability of getting a short-sleeve shirt on the first pick is 4/7.

\n" ); document.write( "The problem asks for the probability that the first shirt is short-sleeve AND the second shirt is short-sleeve. The \"AND\" means the two probabilities must be multiplied to get the answer.

\n" ); document.write( "ANSWER: (5/8)(4/7) = 20/56 = 5/14

\n" ); document.write( "(2) Using \"n choose r\"....

\n" ); document.write( "The number of ways of choosing any 2 of the 8 shirts is \"8 choose 2\": \"C%288%2C2%29=%288%2A7%29%2F%282%2A1%29=28\"

\n" ); document.write( "The number of ways of choosing 2 of the 5 short-sleeve shirts is \"5 choose 2: \"C%285%2C2%29=%285%2A4%29%2F%282%2A1%29=10\"

\n" ); document.write( "The probability of getting two short-sleeve shirts is the number of ways of getting 2 short-sleeve shirts, divided by the total number of ways of choosing 2 of the 8 shirts: 10/28 = 5/14

\n" ); document.write( "ANSWER: (again, of course...) 5/14

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