document.write( "Question 1201706: A closet contains 5 short-sleeve shirts and 3 long-sleeve shirts. Two shirts are chosen from the closet without looking. What is the probability that both shirts have short sleeves? \n" ); document.write( "
Algebra.Com's Answer #836191 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "A student just learning about probability should be able to solve this problem by both of two basic probability methods. \n" ); document.write( "(1) Pick one shirt at a time.... \n" ); document.write( "When picking the first shirt, there are 8 shirts, of which 5 are short sleeve. The probability of getting a short-sleeve shirt on the first pick is 5/8. \n" ); document.write( "When picking the second shirt, there are 7 shirts left, of which 4 are short sleeve. The probability of getting a short-sleeve shirt on the first pick is 4/7. \n" ); document.write( "The problem asks for the probability that the first shirt is short-sleeve AND the second shirt is short-sleeve. The \"AND\" means the two probabilities must be multiplied to get the answer. \n" ); document.write( "ANSWER: (5/8)(4/7) = 20/56 = 5/14 \n" ); document.write( "(2) Using \"n choose r\".... \n" ); document.write( "The number of ways of choosing any 2 of the 8 shirts is \"8 choose 2\": \n" ); document.write( "The number of ways of choosing 2 of the 5 short-sleeve shirts is \"5 choose 2: \n" ); document.write( "The probability of getting two short-sleeve shirts is the number of ways of getting 2 short-sleeve shirts, divided by the total number of ways of choosing 2 of the 8 shirts: 10/28 = 5/14 \n" ); document.write( "ANSWER: (again, of course...) 5/14 \n" ); document.write( " \n" ); document.write( " |