document.write( "Question 1201671: Use the given zero to find the remaining zeros of the polynomial function \r
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Algebra.Com's Answer #836173 by ikleyn(52847)\"\" \"About 
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document.write( "Since (1+i) is a root, the conjugate (1-i) is the root, too.\r\n" );
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document.write( "Using Vieta's theorem, we can write then that the sum of the roots is \"-%28-5%29%2F2%29\" = \"5%2F2\"\r\n" );
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document.write( "    (1+i) + (1-i) + r = \"5%2F2\",   where \"r\" is the third root,\r\n" );
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document.write( "or\r\n" );
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document.write( "    2 + r = \"5%2F2\",  r = \"5%2F2\" - 2 = \"1%2F2\".    ANSWER\r\n" );
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