document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1201671>Question 1201671</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the given zero to find the remaining zeros of the polynomial function \r<BR>\n" );
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document.write( "P(x) =2x^3-5x^2+6x-2;  1+i </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #836168 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=836168\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(x) =2x^3-5x^2+6x-2; 1+i<BR>\n" );
document.write( "There have to be three factors\r<BR>\n" );
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document.write( "1-i is the conjugate of 1+i is also a root\r<BR>\n" );
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document.write( "(x-(1+i))(x-(1-i))<BR>\n" );
document.write( "= x^2-x(1-i)-(1+i)x+1^2-i^2\r<BR>\n" );
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document.write( "=x^2 -x +xi -x-xi+1+1\r<BR>\n" );
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document.write( "= x^2 -2x +2\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282x%5E3-5x%5E2%2B6x-2%29%2F%28x%5E2-2x%2B2%29 ALIGN=MIDDLE  ALT=\"%282x%5E3-5x%5E2%2B6x-2%29%2F%28x%5E2-2x%2B2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  You can divide by co-efficient form<BR>\n" );
document.write( "= 2x-1\r<BR>\n" );
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document.write( "2x-1=0<BR>\n" );
document.write( "x=1/2<BR>\n" );
document.write( "The factors are(1+i),(1-i),(1/2)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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