document.write( "Question 1201677: PLEASE do GIVE CoRRECT AnSwers\r
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document.write( "1. Convert the rectangular form of the complex number 2-2i
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document.write( " into polar form. Show all work and label the modulus and argument.\r
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document.write( "2. Find all cube roots of the complex number 64(cos(219 degree) + i sin (219 degree)). Leave answers in polar form and show all work. \n" );
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Algebra.Com's Answer #836152 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Edit: Sorry I had a brainfart. I mentioned the angle in Q2 when it should have been Q4. \n" ); document.write( "I have fixed the mistake.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll do problem 1 to get you started.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2-2i = 2 + (-2)i \n" ); document.write( "this is written in the form a+bi \n" ); document.write( "a = 2 \n" ); document.write( "b = -2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "r = modulus \n" ); document.write( "r = sqrt(a^2+b^2) \n" ); document.write( "r = sqrt((2)^2+(-2)^2) \n" ); document.write( "r = sqrt(4+4) \n" ); document.write( "r = sqrt(8) \n" ); document.write( "r = sqrt(4*2) \n" ); document.write( "r = sqrt(4)*sqrt(2) \n" ); document.write( "r = 2*sqrt(2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "theta = argument \n" ); document.write( "theta = arctan(b/a) \n" ); document.write( "theta = arctan(-2/2) \n" ); document.write( "theta = arctan(-1) \n" ); document.write( "theta = -45° \n" ); document.write( "Add 360 degrees to find a coterminal angle in the range 0 ≤ theta < 360 \n" ); document.write( "-45+360 = 315\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Summary: \n" ); document.write( "r = 2*sqrt(2) \n" ); document.write( "theta = 315°\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The polar point (r, theta) is (2*sqrt(2), 315°)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another way you could express the answer would be to say the following \n" ); document.write( "z = r*( cos(theta) + i*sin(theta) ) \n" ); document.write( "z = 2*sqrt(2)*( cos(315°) + i*sin(315°) ) \n" ); document.write( "z = 2*sqrt(2)*cis(315°) \n" ); document.write( "where \"cis\" is shorthand for \"cosine i sine\" \n" ); document.write( " \n" ); document.write( " |