document.write( "Question 114937: f(x)= 7x + 5 / 2 - 3x find vertical and horizontal asymptots and given equation. I think the Ha. is 7/3?????????? \n" ); document.write( "
Algebra.Com's Answer #83615 by jim_thompson5910(35256)\"\" \"About 
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Vertical Asymptote:\r
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\n" ); document.write( "\n" ); document.write( "Set the denominator equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"2+-+3x=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"-3x=0-2\"Subtract 2 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-3x=-2\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-2%29%2F%28-3%29\" Divide both sides by -3 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=2%2F3\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "Since \"x=2%2F3\" makes the denominator equal to zero, the vertical asymptote is \"x=2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Horizontal Asymptote:\r
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\n" ); document.write( "\n" ); document.write( "You are close, but you're missing a negative sign\r
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\n" ); document.write( "\n" ); document.write( "Take the leading coefficient of the numerator (which is 7) and the denominator (which is -3, note the negative) and divide them: \"7%2F-3=-7%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "So the horizontal asymptote is \"y=-7%2F3\"
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