document.write( "Question 1201662: Could you please help me with this problem?\r
\n" ); document.write( "\n" ); document.write( "Mr.Cruz wants to borrow $40,000 from the bank to buy the new Ford F-150 Lightning.
\n" ); document.write( "If the bank can offer him a five year loan for 2.5% annual interest compounded monthly,then what will his monthly payments be?
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Algebra.Com's Answer #836132 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Answer: $709.89\r
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\n" ); document.write( "\n" ); document.write( "Work Shown:\r
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\n" ); document.write( "\n" ); document.write( "The formula to use is
\n" ); document.write( "P = (L*i)/( 1-(1+i)^(-n) )
\n" ); document.write( "where,
\n" ); document.write( "P = monthly payment
\n" ); document.write( "L = loan amount
\n" ); document.write( "i = monthly interest rate in decimal form
\n" ); document.write( "n = number of months\r
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\n" ); document.write( "\n" ); document.write( "In this case
\n" ); document.write( "L = 40,000
\n" ); document.write( "i = 0.025/12 = 0.00208333 approximately
\n" ); document.write( "n = 5*12 = 60 months\r
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\n" ); document.write( "\n" ); document.write( "Then,
\n" ); document.write( "P = (L*i)/( 1-(1+i)^(-n) )
\n" ); document.write( "P = (40000*0.00208333)/( 1-(1+0.00208333)^(-60) )
\n" ); document.write( "P = 709.894393670184
\n" ); document.write( "P = 709.89\r
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\n" ); document.write( "\n" ); document.write( "The answer can be confirmed with a calculator such as this one
\n" ); document.write( "https://www.calculator.net/loan-calculator.html
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