document.write( "Question 1201609: Assume that females have pulse rates that are normally distributed with a mean of = 76.0 beats per minute and a standard deviation of o = 12.5 beats per minute. Complete parts (a) through (C)
\n" ); document.write( "k below.\r
\n" ); document.write( "\n" ); document.write( "a. If 1 adult female is randomly selected, find the probability that her pulse rate is between 72 beats per minute and 80 beats per minute
\n" ); document.write( "The probability is
\n" ); document.write( "[Round to tour decimal o aces as needed.
\n" ); document.write( "b. If 25 adult females are randomly selected, find the probability that they have pulse rates with a mean between 72 beats per minute and 80 beats per minute.
\n" ); document.write( "The probability is
\n" ); document.write( "(Round to four decimal places as needed.)
\n" ); document.write( "c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?
\n" ); document.write( "A. Since the original population has a normal distribution. the distribution of sample means is a normal distribution for any sample size
\n" ); document.write( "B. Since the mean pulse rate exceeds 30, the distribution of sample means is a normal distribution for any sample size
\n" ); document.write( "C. Since the distribution is of individuals, not sample means, the distribution is a normal distribution for any sample size
\n" ); document.write( "D. Since the distribution is of sample means, not individuals. the distribution is a normal distribution for an sample size
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Algebra.Com's Answer #836070 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answers:
\n" ); document.write( "(a) 0.2510 (approximate)
\n" ); document.write( "(b) 0.8904 (approximate)
\n" ); document.write( "(c) A. Since the original population has a normal distribution. the distribution of sample means is a normal distribution for any sample size\r
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\n" ); document.write( "\n" ); document.write( "Explanation:\r
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\n" ); document.write( "\n" ); document.write( "Part (a)\r
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\n" ); document.write( "\n" ); document.write( "mu = 76 = population mean pulse rate
\n" ); document.write( "sigma = 12.5 = population standard deviation of the pulse rates
\n" ); document.write( "x = pulse rate of 1 individual\r
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\n" ); document.write( "\n" ); document.write( "Each pulse rate is measured in beats per minute (bpm).\r
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\n" ); document.write( "\n" ); document.write( "Compute the z score for the raw score x = 72
\n" ); document.write( "z = (x-mu)/sigma
\n" ); document.write( "z = (72-76)/12.5
\n" ); document.write( "z = -4/12.5
\n" ); document.write( "z = -0.32\r
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\n" ); document.write( "\n" ); document.write( "Repeat for x = 80
\n" ); document.write( "z = (x-mu)/sigma
\n" ); document.write( "z = (80-76)/12.5
\n" ); document.write( "z = 4/12.5
\n" ); document.write( "z = 0.32\r
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\n" ); document.write( "\n" ); document.write( "The task of finding P(72 < x < 80) is equivalent to P(-0.32 < z < 0.32)\r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I'll be using this Z table
\n" ); document.write( "https://www.ztable.net/
\n" ); document.write( "a similar table can be found in the back of your stats textbook\r
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\n" ); document.write( "\n" ); document.write( "Use such a table to find that
\n" ); document.write( "P(Z < -0.32) = 0.37448
\n" ); document.write( "and
\n" ); document.write( "P(Z < 0.32) = 0.62552\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "P(a < Z < b) = P(Z < b) - P(Z < a)
\n" ); document.write( "P(-0.32 < Z < 0.32) = P(Z < 0.32) - P(Z < -0.32)
\n" ); document.write( "P(-0.32 < Z < 0.32) = 0.62552 - 0.37448
\n" ); document.write( "P(-0.32 < Z < 0.32) = 0.25104
\n" ); document.write( "P(-0.32 < Z < 0.32) = 0.2510\r
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\n" ); document.write( "\n" ); document.write( "Which leads back to
\n" ); document.write( "P(72 < x < 80) = 0.2510\r
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\n" ); document.write( "\n" ); document.write( "There's about a 25.1% chance of randomly selecting a woman who has a pulse rate between 72 bpm and 80 bpm.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You could use a specialized stats calculator such as this one
\n" ); document.write( "https://onlinestatbook.com/2/calculators/normal_dist.html
\n" ); document.write( "as an alternative to using a Z table.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This article goes over a few examples of how to calculate normal distribution probabilities on a TI84 calculator.
\n" ); document.write( "https://www.statology.org/normal-probabilities-ti-84-calculator/\r
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\n" ); document.write( "\n" ); document.write( "Part (b)\r
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\n" ); document.write( "\n" ); document.write( "n = 25 = sample size
\n" ); document.write( "xbar = sample mean = (add up the values)/(number of values)\r
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\n" ); document.write( "\n" ); document.write( "Part (a) refers to selecting 1 woman, while part (b) handles selecting a random sample of 25 women.
\n" ); document.write( "Then we compute xbar and want to determine P(72 < xbar < 80)
\n" ); document.write( "We'll use the aptly named xbar distribution.\r
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\n" ); document.write( "\n" ); document.write( "The xbar distribution has its center at mu = 76 and standard deviation of SE = 2.5, where SE stands for \"standard error\"
\n" ); document.write( "SE = standard error
\n" ); document.write( "SE = sigma/sqrt(n)
\n" ); document.write( "SE = (12.5)/(sqrt(25))
\n" ); document.write( "SE = 2.5\r
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\n" ); document.write( "\n" ); document.write( "Compute the z scores.
\n" ); document.write( "Use xbar in place of x.
\n" ); document.write( "Use the SE value in place of sigma.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If xbar = 72, then,
\n" ); document.write( "z = (xbar-mu)/SE
\n" ); document.write( "z = (72-76)/(2.5)
\n" ); document.write( "z = -4/(2.5)
\n" ); document.write( "z = -1.6\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If xbar = 80, then,
\n" ); document.write( "z = (xbar-mu)/SE
\n" ); document.write( "z = (80-76)/(2.5)
\n" ); document.write( "z = 4/(2.5)
\n" ); document.write( "z = 1.6\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The task of finding P(72 < xbar < 80) is equivalent to P(-1.6 < z < 1.6)\r
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\n" ); document.write( "\n" ); document.write( "Use a Z table to determine the following
\n" ); document.write( "P(Z < -1.6) = 0.0548
\n" ); document.write( "P(Z < 1.6) = 0.9452\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "P(a < Z < b) = P(Z < b) - P(Z < a)
\n" ); document.write( "P(-1.6 < Z < 1.6) = P(Z < 1.6) - P(Z < -1.6)
\n" ); document.write( "P(-1.6 < Z < 1.6) = 0.9452 - 0.0548
\n" ); document.write( "P(-1.6 < Z < 1.6) = 0.8904\r
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\n" ); document.write( "\n" ); document.write( "Which leads back to
\n" ); document.write( "P(72 < xbar < 80) = 0.8904\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "There's about an 89.04% chance of randomly selecting a group of 25 women who have a sample mean (xbar) pulse rate between 72 bpm and 80 bpm.\r
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\n" ); document.write( "\n" ); document.write( "Part (c)\r
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\n" ); document.write( "\n" ); document.write( "At the top of the problem it states \"Assume that females have pulse rates that are normally distributed\"
\n" ); document.write( "So because the population is normally distributed, it indicates the distribution of sample means (xbar distribution) is also normally distributed. This is regardless of the sample size.\r
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\n" ); document.write( "\n" ); document.write( "Therefore, we arrive at the final answer A. Since the original population has a normal distribution. the distribution of sample means is a normal distribution for any sample size
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