document.write( "Question 1201608: If sine theta = 1/3, theta in Quadrant II, find sin theta + pi/6 \n" ); document.write( "
Algebra.Com's Answer #836068 by ikleyn(52787)\"\" \"About 
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\n" ); document.write( "If sine theta = 1/3, theta in Quadrant II, find sin theta + pi/6
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document.write( "Step 1.  If \"sin%28theta%29\" = 1/3  and  \"theta\" in Quadrant II, then it implies\r\n" );
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document.write( "            \"cos%28theta%29\" = \"-sqrt%281-sin%5E2%28theta%29%29\" = \"-sqrt%281+-+1%2F9%29\" = \"-sqrt%288%29%2F3\" = \"%28-2sqrt%282%29%29%2F3\".\r\n" );
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document.write( "Step 2.  \"sin%28theta%2Bpi%2F6%29\" = \"sin%28theta%29%2Acos%28pi%2F6%29\" + \"cos%28theta%29%2Asin%28pi%2F6%29\" = \r\n" );
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document.write( "         = \"%281%2F3%29%2A%28sqrt%283%29%2F2%29\" + \"%28%28-2%2Asqrt%282%29%29%2F3%29%2A%281%2F2%29\" = \"sqrt%283%29%2F6\" - \"%282%2Asqrt%282%29%29%2F6\" = \"%28sqrt%283%29-2%2Asqrt%282%29%29%2F6\" = -0.1827 (rounded).    ANSWER\r\n" );
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