document.write( "Question 1201551: The radioactive isotope of potassium-42, which is a vital in the diagnosis of brain tumors, has a half life of 12.36 hours.\r
\n" ); document.write( "\n" ); document.write( "Determine the exponential decay model that represents the mass of potassium-42?\r
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Algebra.Com's Answer #835988 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "... has a half life of 12.36 hours.
\n" ); document.write( "Determine the exponential decay model that re....
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\n" ); document.write( "\n" ); document.write( "\"y=p%281%2F2%29%5E%28x%2F12.36%29\", unless you need some other specific form.\r
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\n" ); document.write( "\n" ); document.write( "Another way
\n" ); document.write( "\"y=pe%5E%28kx%29\"
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\n" ); document.write( "\"ln%28y%29=ln%28p%29%2Bln%28e%5E%28kx%29%29\"
\n" ); document.write( "\"ln%28y%29=ln%28p%29%2Bkx%2Aln%28e%29\"
\n" ); document.write( "\"ln%28y%29-ln%28p%29=kx\"\r
\n" ); document.write( "\n" ); document.write( "\"k=%281%2Fx%29%28ln%28y%29-ln%28p%29%29\"
\n" ); document.write( "and using your given half life information
\n" ); document.write( "\"k=%281%2F12.36%29%28ln%280.5%29-ln%281%29%29\"
\n" ); document.write( "\"k=%281%2F12.36%29%28-ln%282%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y=pe%5E%28-%28ln%282%29%2F12.36%29x%29\"---------------y=pe^(-(ln(2)/12.36)x)\r
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\n" ); document.write( "\"k=-0.0561\"
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