document.write( "Question 1200840: A manufacturer knows that their items have a normally distributed length, with a mean of 14.3 inches, and standard deviation of 1.7 inches.\r
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document.write( "If 12 items are chosen at random, what is the probability that their mean length is less than 14.2 inches?\r
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document.write( "Enter your answers as numbers accurate to 4 decimal places.
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Algebra.Com's Answer #835985 by Theo(13342)![]() ![]() You can put this solution on YOUR website! mean is 14.3 \n" ); document.write( "sandard deviation is 1.7 \n" ); document.write( "sample size is 12. \n" ); document.write( "standard error is 1.7 / sqrt(12) = .4907477288. \n" ); document.write( "probability that their mean length is less than 14.2 would be .4193 using the online calculator at https://davidmlane.com/hyperstat/z_table.html \n" ); document.write( "the probability is .4192663762 using the ti-84 plus scientific calculator. \n" ); document.write( "here's what the results look like using the online calculator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the key is that you have to use the standard error, rather than the standard deviation, because you are looking for the mean of a sample of size greater than 1. \n" ); document.write( " \n" ); document.write( " |