document.write( "Question 1201509: There were twice as many boys as girls in a Swimming Club. After 40 boys and 15 girls left the club, the number of girls who remained was 3/5 of the number of boys who remained in the club. How many children were there in the club at first? \n" ); document.write( "

Algebra.Com's Answer #835899 by ikleyn(52782) $\"\"$ $\"About$

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\n" ); document.write( "There were twice as many boys as girls in a Swimming Club.
\n" ); document.write( "After 40 boys and 15 girls left the club, the number of girls who remained
\n" ); document.write( "was 3/5 of the number of boys who remained in the club.
\n" ); document.write( "How many children were there in the club at first?
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document.write( "Originally  x girls ans 2x boys.\r\n" );
document.write( "The number x is unknown, and our goal is to find x.\r\n" );
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document.write( "Agter After 40 boys and 15 girls left the club,\r\n" );
document.write( "(x-15) girls and (2x-40) boys remained.\r\n" );
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document.write( "The problem dictates us this proportion\r\n" );
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document.write( "     = 3/5.\r\n" );
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document.write( "To solve it, first cross multiply\r\n" );
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document.write( "    5(x-15) = 3*(2x-40).\r\n" );
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document.write( "Next simplify and find x\r\n" );
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document.write( "    5x - 75 = 6x - 120\r\n" );
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document.write( "    120 - 75 = 6x - x\r\n" );
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document.write( "       45    =    x.\r\n" );
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document.write( "ANSWER.  Originally, there were 45 girls and 2*45 = 90 boys.\r\n" );
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document.write( "         The total was 45 + 90 = 135 children.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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