document.write( "Question 1201501: At time=0, there are 6,000 grams of a radioactive material present. The half-life of the element is 18 years. In how many years will there be 115 grams remaining? Round your answer to the nearest 0.01 years.\r
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Algebra.Com's Answer #835891 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"y=p%281%2F2%29%5E%28x%2Fh%29\"
\n" ); document.write( "p, initial amount
\n" ); document.write( "h, half life
\n" ); document.write( "x, amount time passage
\n" ); document.write( "y, amount after x time\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%28y%29%29=log%28%28p%29%29%2Blog%28%28%281%2F2%29%5E%28x%2Fh%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28y%29%29=log%28%28p%29%29%2B%28x%2Fh%29log%28%281%2F2%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28y%29%29-log%28%28p%29%29=%28x%2Fh%29%28-log%28%282%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28p%29%29-log%28%28y%29%29=%28x%2Fh%29log%28%282%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28p%2Fy%29%29%28h%2Flog%28%282%29%29%29=x\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=%28h%2Flog%28%282%29%29%29log%28%28p%2Fy%29%29%29\"
\n" ); document.write( "Your values to substitute are
\n" ); document.write( "\"system%28h=18%2Cy=115%2Cp=6000%29\"
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