document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=114828>Question 114828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "2 - 3x < or equal to 8-x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83589 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83589\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2-3X<=8-X<BR>\n" );
document.write( "-3X+X<=8-2<BR>\n" );
document.write( "-2X<=6 DIVIDING BY A NEGATIVE INTEGER CHANGES THE < TO A > SIGN.<BR>\n" );
document.write( "X>=6/-2<BR>\n" );
document.write( "X>=-3 ANSWER.PROOF<BR>\n" );
document.write( "LET X=-2.9<BR>\n" );
document.write( "2-3*-2.9<=8-(-2.9)<BR>\n" );
document.write( "2+8.7<=8+2.9<BR>\n" );
document.write( "10.7<=10.9 </SPAN>\n" );
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