document.write( "Question 1200932: Given: In △ ABC, segment AC = segment BC and segment AB ≠ segment AC. segment AD is a median.\r
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Algebra.Com's Answer #835881 by Edwin McCravy(20056)\"\" \"About 
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document.write( "Given: \r\n" );
document.write( "In △ ABC, segment AC = segment BC and segment AB ≠ segment AC. segment AD is a median.\r\n" );
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document.write( "Prove: segment AD cannot be perpendicular to segment BC\r\n" );
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document.write( "Assume (for contradiction) that AD is perpendicular to BC\r\n" );
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document.write( "CD = BD                                  because AD is a median\r\n" );
document.write( "AD is perpendicular to BC                by assumption (for contradiction)\r\n" );
document.write( "Angle ADC = Angle ABD                    Because AD perp. to BC\r\n" );
document.write( "AD = AD                                  symmetric property \r\n" );
document.write( "triangle ACD congruent to triangle ABD   SAS\r\n" );
document.write( "AB = AC                                  C.P.C.T.\r\n" );
document.write( "Contradiction to segment AB ≠ segment AC. \r\n" );
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document.write( "Edwin
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